Can I use shared library created in C++ in a C program?

Question

I am creating programs using C. However, I require to use a lot of libraries that have API\'s only for C++. So, is it possible that I can create a shared object in C++ and t

Answer 1

You want something more like this (and here I will use a slightly more meaningful example):

C/C++ header - animal.h

#ifndef ANIMAL_H
#define ANIMAL_H

#ifdef __cplusplus
class Animal {
public:
    Animal() : age(0), height(0) {}
    Animal(int age, float height) : age(age), height(height) {}
    virtual ~Animal() {}

    int   getAge();
    void  setAge(int new_age);

    float getHeight();
    void  setHeight(float new_height);

private:
    int age;
    float height; // in metres!
};
#endif /* __cplusplus */

#ifdef __cplusplus
extern "C" {
#endif
    struct animal; // a nice opaque type

    struct animal *animal_create();
    struct animal *animal_create_init(int age, float height);
    void           animal_destroy(struct animal *a);

    void           animal_setage(struct animal *a, int new_age);
    void           animal_setheight(struct animal *a, float new_height);
    int            animal_getage(struct animal *a);
    float          animal_getheight(struct animal *a);
#ifdef __cplusplus
}
#endif

#endif /* ANIMAL_H */

C++ animal implementation file - animal.cpp

#include "animal.h"
#define TO_CPP(a) (reinterpret_cast(a))
#define TO_C(a)   (reinterpret_cast(a))

void  Animal::setAge(int new_age) { this->age = new_age; }
int   Animal::getAge() { return this->age; }
void  Animal::setHeight(float new_height) { this->height = new_height; }
float Animal::getHeight() { return this->height; }

animal *animal_create() {
    animal *a = TO_C(new Animal);
    return a;
}

animal *animal_create_init(int age, float height) {
    animal *a = TO_C(new Animal(age, height));
    return a;
}

void animal_destroy(animal *a) {
    delete TO_CPP(a);
}

void animal_setage(animal *a, int new_age) {
    TO_CPP(a)->setAge(new_age);
}

void animal_setheight(animal *a, float new_height) {
    TO_CPP(a)->setHeight(new_height);
}

int animal_getage(animal *a) {
    TO_CPP(a)->getAge();
}

float animal_getheight(animal *a) {
    TO_CPP(a)->getHeight();
}

C client code - main.c

#include "animal.h"
#include 

int main()
{
    // 6'0" 25yo (perhaps a human? :P)
    struct animal *a = animal_create(25, 1.83); 

    animal_setage(a, 26); // birthday
    printf("Age: %d\nHeight: %f", animal_getage(a), animal_getheight(a));

    animal_destroy(a);
    return 0;
}

C++ client code - main.cpp

#include "animal.h"
#include 

int main()
{
    // 6'0" 25yo (perhaps a human? :P)
    Animal* a = new Animal(25, 1.83);
    a->setAge(26); // birthday
    std::cout << "Age:    " << a->getAge() << std::endl;
    std::cout << "Height: " << a->getHeight();

    delete a;
    return 0;
}

So when you compile the library, you compile animal.cpp with a C++ compiler. You can then link to it with C code, and use the animal_xxx functions.

Note the use of struct animal and Animal. Animal is a normal C++ type. It's exactly what it looks like. struct animal, on the other hand, is an "opaque" type. That means that your C program can see it's there, and can have one, but it doesn't know what is inside it. All it knows is that it has a function that takes a struct animal*.

In a real library you will want to have customisation points for memory allocation. So assuming this is the library libjungle, you probably want at least jungle_setmalloc and jungle_setfree with sensible defaults. You can then set up the global new and delete in libjungle's C++ code to use these user-defined functions.