Bash script, watch folder, execute command

Question

I am trying to create a bash script with 2 parameters:

• a directory
• a command.

I want to watch the

Answer 1

#!/bin/bash

# Author: Devonte
# NGINX WATCH DAEMON
# Place file in root of nginx folder /etc/nginx
# This will test your nginx config on any change and
# if there are no problems it will reload your configuration
# USAGE: sh nginx-watch.sh

dir=`dirname $0`

checksum_initial=`tar -cf - $dir | md5sum | awk '{print $1}'`
checksum_now=$checksum_initial

# Start nginx
nginx

while true
do
    sleep 3
    checksum_now=`tar -cf - $dir | md5sum | awk '{print $1}'`

    if [ $checksum_initial != $checksum_now ]; then
        echo "[ NGINX ] A configuration file changed. Reloading..."
        nginx -t && nginx -s reload;
    fi

    checksum_initial=$checksum_now
done