How do I find the number of arguments passed to a Bash script?

Question

How do I find the number of arguments passed to a Bash script?

This is what I have currently:

#!/bin/bash
i=0
for var in \"$@\"
do
  i=i+1
done
         


        

Answer 1

Below is the easy one -

cat countvariable.sh

echo "$@" |awk '{for(i=0;i<=NF;i++); print i-1 }'

Output :

#./countvariable.sh 1 2 3 4 5 6
6
#./countvariable.sh 1 2 3 4 5 6 apple orange
8