An array contains both positive and negative elements, find the maximum subarray whose sum equals 0.
Following solution finds max length subarray with a given sum k without using dynamic programming, but using simple rescursion. Here i_s is start index and i_e is end index for the current value of sum
##Input the array and sum to be found(0 in your case)
a = map(int,raw_input().split())
k = int(raw_input())
##initialize total sum=0
totalsum=0
##Recursive function to find max len 0
def findMaxLen(sumL,i_s,i_e):
if i_s0:
if sumL==k:
print i_s, i_e
return (i_s,i_e)
else:
x = findMaxLen(sumL-a[i_s],i_s+1,i_e)
y = findMaxLen(sumL-a[i_e],i_s,i_e-1)
if x[1]-x[0]>y[1]-y[0]:
return x
else:
return y
else:
##Result not there
return (-1,-1)
## find total sum
for i in range(len(a)):
totalsum += a[i]
##if totalsum==0, max array is array itself
if totalsum == k:
print "seq found at",0,len(a)-1
##else use recursion
else:
print findMaxLen(totalsum,0,len(a)-1)
Time complexity is O(n) and space complexity is O(n) due to recursive memory stack