An array contains both positive and negative elements, find the maximum subarray whose sum equals 0.
This is one the same lines as suggested by Gevorg but I have used a hash map for quick lookup. O(n) complexity used extra space though.
private static void subArraySumsZero()
{
int [] seed = new int[] {1,2,3,4,-9,6,7,-8,1,9};
int currSum = 0;
HashMap sumMap = new HashMap();
for(int i = 0 ; i < seed.length ; i ++)
{
currSum += seed[i];
if(currSum == 0)
{
System.out.println("subset : { 0 - " + i + " }");
}
else if(sumMap.get(currSum) != null)
{
System.out.println("subset : { "
+ (sumMap.get(currSum) + 1)
+ " - " + i + " }");
sumMap.put(currSum, i);
}
else
sumMap.put(currSum, i);
}
System.out.println("HASH MAP HAS: " + sumMap);
}
The output generated has index of elements (zero based):
subset : { 1 - 4 }
subset : { 3 - 7 }
subset : { 6 - 8 }