Counting the Number of keywords in a dictionary in python

Question

I have a list of words in a dictionary with the value = the repetition of the keyword but I only want a list of distinct words so I wanted to count the number of keywords. I

Answer 1

Some modifications were made on posted answer UnderWaterKremlin to make it python3 proof. A surprising result below as answer.

System specs:

• python =3.7.4,
• conda = 4.8.0
• 3.6Ghz, 8 core, 16gb.

import timeit

d = {x: x**2 for x in range(1000)}
#print (d)
print (len(d))
# 1000

print (len(d.keys()))
# 1000

print (timeit.timeit('len({x: x**2 for x in range(1000)})', number=100000))        # 1

print (timeit.timeit('len({x: x**2 for x in range(1000)}.keys())', number=100000)) # 2

Result:

1) = 37.0100378

2) = 37.002148899999995

So it seems that len(d.keys()) is currently faster than just using len().