Python list iterator behavior and next(iterator)

Question

Consider:

>>> lst = iter([1,2,3])
>>> next(lst)
1
>>> next(lst)
2

So, advancing the iterator is, as expected, ha

Answer 1

What is happening is that next(a) returns the next value of a, which is printed to the console because it is not affected.

What you can do is affect a variable with this value:

>>> a = iter(list(range(10)))
>>> for i in a:
...    print(i)
...    b=next(a)
...
0
2
4
6
8