How can I find the link URL by link text with XPath?

Question

I have a well formed XHTML page. I want to find the destination URL of a link when I have the text that is linked.

Example

Answer 1

if you are using html agility pack use getattributeValue:

$doc2.DocumentNode.SelectNodes("//div[@class='className']/div[@class='InternalClass']/a[@class='InternalClass']").GetAttributeValue("href","")