How do I get the path and name of the file that is currently executing?

Question

I have scripts calling other script files but I need to get the filepath of the file that is currently running within the process.

For example, let\'s say I have th

Answer 1

You can use inspect.stack()

import inspect,os
inspect.stack()[0]  => (, 'g:\\Python\\Test\\_GetCurrentProgram.py', 15, '', ['print inspect.stack()[0]\n'], 0)
os.path.abspath (inspect.stack()[0][1]) => 'g:\\Python\\Test\\_GetCurrentProgram.py'