Is there a way using Python\'s standard library to easily determine (i.e. one function call) the last day of a given month?
If the standard library doesn\'t support
Here is a long (easy to understand) version but takes care of leap years.
cheers, JK
def last_day_month(year, month):
leap_year_flag = 0
end_dates = {
1: 31,
2: 28,
3: 31,
4: 30,
5: 31,
6: 30,
7: 31,
8: 31,
9: 30,
10: 31,
11: 30,
12: 31
}
# Checking for regular leap year
if year % 4 == 0:
leap_year_flag = 1
else:
leap_year_flag = 0
# Checking for century leap year
if year % 100 == 0:
if year % 400 == 0:
leap_year_flag = 1
else:
leap_year_flag = 0
else:
pass
# return end date of the year-month
if leap_year_flag == 1 and month == 2:
return 29
elif leap_year_flag == 1 and month != 2:
return end_dates[month]
else:
return end_dates[month]