Get column index from label in a data frame

Question

Say we have the following data frame:

> df
  A B C
1 1 2 3
2 4 5 6
3 7 8 9

We can select column \'B\' from its index:

&g         


        

Answer 1

Following on from chimeric's answer above:

To get ALL the column indices in the df, so i used:

which(!names(df)%in%c()) 

or store in a list:

indexLst<-which(!names(df)%in%c())