Compare integer in bash, unary operator expected

Question

The following code gives

[: -ge: unary operator expected

when

i=0

if [ $i -ge 2 ]
then
    #some code
fi
         


        

Answer 1

Your piece of script works just great. Are you sure you are not assigning anything else before the if to "i"?

A common mistake is also not to leave a space after and before the square brackets.