How can a time function exist in functional programming?

Question

I\'ve to admit that I don\'t know much about functional programming. I read about it from here and there, and so came to know that in functional programming, a function retu

Answer 1

In Haskell one uses a construct called monad to handle side effects. A monad basically means that you encapsulate values into a container and have some functions to chain functions from values to values inside a container. If our container has the type:

data IO a = IO (RealWorld -> (a,RealWorld))

we can safely implement IO actions. This type means: An action of type IO is a function, that takes a token of type RealWorld and returns a new token, together with a result.

The idea behind this is that each IO action mutates the outside state, represented by the magical token RealWorld. Using monads, one can chain multiple functions that mutate the real world together. The most important function of a monad is >>=, pronounced bind:

(>>=) :: IO a -> (a -> IO b) -> IO b

>>= takes one action and a function that takes the result of this action and creates a new action out of this. The return type is the new action. For instance, let's pretend there is a function now :: IO String, which returns a String representing the current time. We can chain it with the function putStrLn to print it out:

now >>= putStrLn

Or written in do-Notation, which is more familiar to an imperative programmer:

do currTime <- now
   putStrLn currTime

All this is pure, as we map the mutation and information about the world outside to the RealWorld token. So each time, you run this action, you get of course a different output, but the input is not the same: the RealWorld token is different.