How to remove 2nd occurrence of an item in a list using remove() without removing 1st occurrence in Python

Question

a = [9,8,2,3,8,3,5]

How to remove 2nd occurrence of 8 without removing 1st occurrence of 8 using remove().

Answer 1

remove() removes the first item from the list which matches the specified value. To remove the second occurrence, you can use del instead of remove.The code should be simple to understand, I have used count to keep track of the number of occurrences of item and when count becomes 2, the element is deleted.

a = [9,8,2,3,8,3,5]
item  = 8
count = 0
for i in range(0,len(a)-1):
        if(item == a[i]):
               count =  count + 1
               if(count == 2):
                      del a[i]
                      break
print(a)