Distinct() with lambda?

Question

Right, so I have an enumerable and wish to get distinct values from it.

Using System.Linq, there\'s of course an extension method called Distinct<

Answer 1

Take another way:

var distinctValues = myCustomerList.
Select(x => x._myCaustomerProperty).Distinct();

The sequence return distinct elements compare them by property '_myCaustomerProperty' .