Distinct() with lambda?

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南旧
南旧 2020-11-22 06:04

Right, so I have an enumerable and wish to get distinct values from it.

Using System.Linq, there\'s of course an extension method called Distinct<

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  •  面向向阳花
    2020-11-22 06:32

    Shorthand solution

    myCustomerList.GroupBy(c => c.CustomerId, (key, c) => c.FirstOrDefault());
    

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