Distinct() with lambda?

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南旧
南旧 2020-11-22 06:04

Right, so I have an enumerable and wish to get distinct values from it.

Using System.Linq, there\'s of course an extension method called Distinct<

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  •  清歌不尽
    2020-11-22 06:26

    IEnumerable filteredList = originalList
      .GroupBy(customer => customer.CustomerId)
      .Select(group => group.First());
    

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