How to get the filename without the extension from a path in Python?

Question

How to get the filename without the extension from a path in Python?

For instance, if I had "/path/to/some/file.txt", I would want "

Answer 1

On Windows system I used drivername prefix as well, like:

>>> s = 'c:\\temp\\akarmi.txt'
>>> print(os.path.splitext(s)[0])
c:\temp\akarmi

So because I do not need drive letter or directory name, I use:

>>> print(os.path.splitext(os.path.basename(s))[0])
akarmi