How to parse “yyyy-MM-dd'T'HH:mm:ss.SSSXXX” date format to simple in Android? [duplicate]

Answer 1

If you are using java, you can use SimpeDateFormat with patterns:

        String date = "2018-01-09T11:11:02.0+03:00";
        SimpleDateFormat dateformat = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSSXXX");
        SimpleDateFormat output = new SimpleDateFormat("dd.MM.yyyy hh:mm");
        Date d = null;
        try {
            d = dateformat.parse(date /*your date as String*/);
        } catch (ParseException e) {
            e.printStackTrace();
        }
        String formattedDate = output.format(d);

        Log.d("Date format", "output date :" + formattedDate);

The output is :

D/Date format: output date :09.01.2018 09:11

EDIT : Thanks to @OleV.V., for API > 26, or using ThreeTenABP we can use

DateTimeFormatter, we can do something like that

    String date = "2018-01-09T11:11:02.0+03:00";
    DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyy-MM-dd'T'HH:mm:ss.SSSXXX");
    DateTimeFormatter formatterOut = DateTimeFormatter.ofPattern("dd.MM.yyyy hh:mm");
    LocalDate parsedDate = LocalDate.parse(date, formatter);

    String formattedDate = formatterOut.format(parsedDate);
    Log.d("Date format", "output date :" + formattedDate);