Multiple slideshows on one page makes the first one not work anymore

Question

First of all I know this question\'s been asked before the answer wasn\'t solving my problem so I\'d like to ask it again : I used a Slideshow code from \"W3school\" wich pr

Answer 1

I've created a solution here:

var sliderObjects = [];
createSliderObjects();

function plusDivs(obj, n) {
  var parentDiv = $(obj).parent();
  var matchedDiv;
  $.each(sliderObjects, function(i, item) {
    if ($(parentDiv[0]).attr('id') == $(item).attr('id')) {
      matchedDiv = item;
      return false;
    }
  });
  matchedDiv.slideIndex=matchedDiv.slideIndex+n;
  showDivs(matchedDiv, matchedDiv.slideIndex);
}

function createSliderObjects() {
  var sliderDivs = $('.slider');
  $.each(sliderDivs, function(i, item) {
    var obj = {};
    obj.id = $(item).attr('id');
    obj.divContent = item;
    obj.slideIndex = 1;
    obj.slideContents = $(item).find('.mySlides');
    showDivs(obj, 1);
    sliderObjects.push(obj);
  });
}

function showDivs(divObject, n) {
  debugger;
  var i;
  if (n > divObject.slideContents.length) {
    divObject.slideIndex = 1
  }
  if (n < 1) {
    divObject.slideIndex = divObject.slideContents.length
  }
  for (i = 0; i < divObject.slideContents.length; i++) {
    divObject.slideContents[i].style.display = "none";
  }
  divObject.slideContents[divObject.slideIndex - 1].style.display = "block";
}

Manual Slideshow


  
  
  
  

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you can now add as many divs for sliders with 'slider' class and a unique id.