Passing address, but it is working like call by value in C?

Question

Hello I am a beginner in C programming language. Recently I read about call by value and call by address. I have learned that in call by address changes in the called functi

Answer 1

You are simply setting the value of the pointer in the function, not the value of the pointed to variable. The function should use the following code:

*ptr = y;

This derefences the pointer (exposing the value pointed to), and therefore when you use the equals operator, the memory pointed at is modified, not the pointer itself. I hope this helps to clarify things.