Passing an array as an argument to a function in C

Question

I wrote a function containing array as argument, and call it by passing value of array as follows.

void arraytest(int a[])
{
    // changed the array a
    a         


        

Answer 1

Arrays are always passed by reference if you use a[] or *a:

int* printSquares(int a[], int size, int e[]) {   
    for(int i = 0; i < size; i++) {
        e[i] = i * i;
    }
    return e;
}

int* printSquares(int *a, int size, int e[]) {
    for(int i = 0; i < size; i++) {
        e[i] = i * i;
    }
    return e;
}