Split string by space and character as delimiter in Oracle with regexp_substr

Question

I\'m trying to split a string with regexp_subtr, but i can\'t make it work.

So, first, i have this query

select regexp_substr(\'Helloworld - test!\'          


        

Answer 1

Slight improvement on MT0's answer. Dynamic count using regexp_count and proves it handles nulls where the format of [^delimiter]+ as a pattern does NOT handle NULL list elements. More info on that here: Split comma seperated values to columns

SQL> with tbl(str) as (
  2    select ' - Hello world - test-test! -  - test - ' from dual
  3  )
  4  SELECT LEVEL AS Occurrence,
  5         REGEXP_SUBSTR( str ,'(.*?)([[:space:]]-[[:space:]]|$)', 1, LEVEL, NULL, 1 ) AS split_value
  6  FROM   tbl
  7  CONNECT BY LEVEL <= regexp_count(str, '[[:space:]]-[[:space:]]')+1;

OCCURRENCE SPLIT_VALUE
---------- ----------------------------------------
         1
         2 Hello world
         3 test-test!
         4
         5 test
         6

6 rows selected.

SQL>