Split string by space and character as delimiter in Oracle with regexp_substr

Question

I\'m trying to split a string with regexp_subtr, but i can\'t make it work.

So, first, i have this query

select regexp_substr(\'Helloworld - test!\'          


        

Answer 1

If i understood correctly, this will help you. Currently you are getting output as Helloworld(with space at the end). So i assume u don't want to have space at the end. If so you can simply use the space in the delimiter also like.

select regexp_substr('Helloworld - test!' ,'[^ - ]+',1,1)from dual;

OUTPUT
Helloworld(No space at the end)

As u mentioned in ur comment if u want two columns output with Helloworld and test!. you can do the following.

select regexp_substr('Helloworld - test!' ,'[^ - ]+',1,1),
       regexp_substr('Helloworld - test!' ,'[^ - ]+',1,3) from dual;

OUTPUT
col1         col2
Helloworld   test!