Given:
a = [[1,2],[3,4],[5,6],[7,8]] b = 3
I would like to remove an item of a that has b as it\'s first item. S
a
b
for i in a[:-1]: if i[0]==b: a.remove(i)
What about this?
The output is
[[1, 2], [5, 6], [7, 8]]