Does itertools.product evaluate its arguments lazily?

Question

The following never prints anything in Python 3.6

from itertools import product, count

for f in product(count(), [1,2]): 
    print(f)

Ins

Answer 1

I found that

for tup in ((x,y) for x in count() for y in [1,2]):
    print(tup)

does what I expect. This is odd given that it is listed as equivelent in the docs. This seems like a bug in itertools.product, but it seems unlikely given how standard it is.