I wish to calculate the time it took for an API to return a value. The time taken for such an action is in the space of nano seconds. As the API is a C++ class/function, I a
If the idea is to have a minimalistic struct that you can use for quick tests, then I suggest you just copy and paste anywhere in your C++ file right after the #include's. This is the only instance in which I sacrifice Allman-style formatting.
You can easily adjust the precision in the first line of the struct. Possible values are: nanoseconds, microseconds, milliseconds, seconds, minutes, or hours.
#include
struct MeasureTime
{
using precision = std::chrono::microseconds;
std::vector times;
std::chrono::steady_clock::time_point oneLast;
void p() {
std::cout << "Mark "
<< times.size()/2
<< ": "
<< std::chrono::duration_cast(times.back() - oneLast).count()
<< std::endl;
}
void m() {
oneLast = times.back();
times.push_back(std::chrono::steady_clock::now());
}
void t() {
m();
p();
m();
}
MeasureTime() {
times.push_back(std::chrono::steady_clock::now());
}
};
MeasureTime m; // first time is already in memory
doFnc1();
m.t(); // Mark 1: next time, and print difference with previous mark
doFnc2();
m.t(); // Mark 2: next time, and print difference with previous mark
doStuff = doMoreStuff();
andDoItAgain = doStuff.aoeuaoeu();
m.t(); // prints 'Mark 3: 123123' etc...
Mark 1: 123
Mark 2: 32
Mark 3: 433234
If you want the report afterwards, because for example your code in between also writes to standard output. Then add the following function to the struct (just before MeasureTime()):
void s() { // summary
int i = 0;
std::chrono::steady_clock::time_point tprev;
for(auto tcur : times)
{
if(i > 0)
{
std::cout << "Mark " << i << ": "
<< std::chrono::duration_cast(tprev - tcur).count()
<< std::endl;
}
tprev = tcur;
++i;
}
}
So then you can just use:
MeasureTime m;
doFnc1();
m.m();
doFnc2();
m.m();
doStuff = doMoreStuff();
andDoItAgain = doStuff.aoeuaoeu();
m.m();
m.s();
Which will list all the marks just like before, but then after the other code is executed. Note that you shouldn't use both m.s() and m.t().