Why is the exit code 255 instead of -1 in Perl?

Question

Why is it that when I shift the exit code, $?, in Perl by eight, I get 255 when I expect it to be -1?

Answer 1

Perl returns a subprocess exit code in the same manner as the C runtime library macro WEXITSTATUS, which has the following description in wait(2):

   WEXITSTATUS(status)
          evaluates to the least significant eight bits of the return code
          of the child which terminated, which may have been  set  as  the
          argument  to  a  call  to exit() or as the argument for a return
          statement in the main program.  This macro can only be evaluated
          if WIFEXITED returned non-zero.

The important part here is the least significant eight bits. This is why you are getting an exit code of 255. The perlvar man page describes $? as follows:

   $?      The status returned by the last pipe close, backtick (‘‘) com-
           mand, successful call to wait() or waitpid(), or from the sys-
           tem() operator.  This is just the 16-bit status word returned
           by the wait() system call (or else is made up to look like it).
           Thus, the exit value of the subprocess is really ("$? >> 8"),
           and "$? & 127" gives which signal, if any, the process died
           from, and "$? & 128" reports whether there was a core dump.

There is no special handling here for negative numbers in the exit code.