How to check if array is already sorted

Question

so how to make such logic

int[] arr = {2, 5, 3};

if (/* arr is sorted */)
    ....
else 
    ...

Its bad that method Array.sort is void

Answer 1

A shorter version:

[0,1,2,3,4].reduce((a,v) => (a!==false) && (a <= v) ? v : false, -Infinity)
[4,3,1,2,0].reduce((a,v) => (a!==false) && (a >= v) ? v : false, +Infinity)

Be careful, as in some cases it isn't effective because it will loop through entire array without breaking prematurely.

Array.prototype.reduce()