Why isn't “0f” treated as a floating point literal in C++?

Question

Why isn\'t 0f treated as a floating point literal in C++?

#include 

using namespace std;

int main(){
  cout << 0f <&l         


        

Answer 1

Here's a 'because' for you: if an int constant with an f suffix was automatically converted to float, then 0x0f would be ambiguous.