How to pass parameters from bash to php script?

Question

I have done a a bash script which run php script. It works fine without parameters but when I add parameters (id and url), there are some errors:

PHP Deprec         


        

Answer 1

-- Option 1: php-cgi --

Use 'php-cgi' in place of 'php' to run your script. This is the simplest way as you won't need to specially modify your php code to work with it:

php-cgi -f /my/script/file.php id=19 myvar=xyz

-- Option 2: if you have a web server --

If the php file is on a web server you can use 'wget' on the command line:

wget 'http://localhost/my/script/file.php?id=19&myvar=xyz'

OR:

wget -q -O - "http://localhost/my/script/file.php?id=19&myvar=xyz"

-- Accessing the variables in php --

In both option 1 & 2 you access these parameters like this:

$id = $_GET["id"];
$myvar = $_GET["myvar"];