C# Method Resolution, long vs int

Question

class foo
{
  public void bar(int i) { ... };
  public void bar(long i) { ... };
}


foo.bar(10);

I would expect this code to give me some error, o

Answer 1

The int version of bar is being called, because 10 is an int literal and the compiler will look for the method which closest matches the input variable(s). To call the long version, you'll need to specify a long literal like so: foo.bar(10L);

Here is a post by Eric Lippert on much more complicated versions of method overloading. I'd try and explain it, but he does a much better job and I ever could: http://blogs.msdn.com/b/ericlippert/archive/2006/04/05/odious-ambiguous-overloads-part-one.aspx

from the C# 4.0 Specification:

Method overloading permits multiple methods in the same class to have the same name as long as they have unique signatures. When compiling an invocation of an overloaded method, the compiler uses overload resolution to determine the specific method to invoke. Overload resolution finds the one method that best matches the arguments or reports an error if no single best match can be found. The following example shows overload resolution in effect. The comment for each invocation in the Main method shows which method is actually invoked.

 class Test {   
      static void F() {
        Console.WriteLine("F()");   
      }     
      static void F(object x) {
        Console.WriteLine("F(object)");     
      }
      static void F(int x) {
        Console.WriteLine("F(int)");    
      }
      static void F(double x) {
        Console.WriteLine("F(double)");     
      }
      static void F(T x) {
        Console.WriteLine("F(T)");   
      }
      static void F(double x, double y) {
        Console.WriteLine("F(double,double)");  
      }     

      static void Main() {
        F();                // Invokes F()
        F(1);           // Invokes F(int)
        F(1.0);         // Invokes F(double)
        F("abc");       // Invokes F(object)
        F((double)1);       // Invokes F(double)
        F((object)1);       // Invokes F(object)
        F(1);      // Invokes F(T)
        F(1, 1);        // Invokes F(double, double)
      } 
}

As shown by the example, a particular method can always be selected by explicitly casting the arguments to the exact parameter types and/or explicitly supplying type arguments.