Using DATEADD in sqlalchemy

Question

How can I rewrite the following sql statement with sqlalchemy in python. I have been searching for 30 mins but still couldn\'t find any solutions.

DATEADD(NO         


        

Answer 1

For completeness sake, here is how you'd generate that exact SQL with using sqlalchemy.sql.func:

from sqlalchemy.sql import func
from sqlalchemy.sql.expression import bindparam
from sqlalchemy import Interval

tomorrow = func.dateadd(func.now(), bindparam('tomorrow', timedelta(days=1), Interval()))

which results in:

>>> from sqlalchemy.sql import func
>>> func.dateadd(func.now(), bindparam('tomorrow', timedelta(days=1), Interval(native=True)))

>>> str(func.dateadd(func.now(), bindparam('tomorrow', timedelta(days=1), Interval(native=True))))
'dateadd(now(), :tomorrow)'

Alternatively you could use a text() object to specify the interval instead:

from sqlalchemy.sql import func
from sqlalchemy.sql.expression import text

tomorrow = func.dateadd(func.now(), text('interval 1 day'))