Swapping objects using pointers

Question

I\'m trying to swap objects for a homework problem that uses void pointers to swap objects. The declaration of my function has to be:

void swap(void *a, voi         


        

Answer 1

Parameters are like local variables, with values copied into them before the function starts executing. This prototype:

void swap(void *a, void *b, size_t size);

Means that the two addresses are copied into new variables called a and b. So if you change what is stored in a and b, nothing you do will have an any effect after swap returns.