Swift 4 decode simple root level json value

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猫巷女王i
猫巷女王i 2020-12-03 17:38

According to the JSON standard RFC 7159, this is valid json:

22

How do I decode this into an Int using swift4\'s decodable? This does not w

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  •  挽巷
    挽巷 (楼主)
    2020-12-03 18:15

    It works with good ol' JSONSerialization and the .allowFragments reading option. From the documentation:

    allowFragments

    Specifies that the parser should allow top-level objects that are not an instance of NSArray or NSDictionary.

    Example:

    let json = "22".data(using: .utf8)!
    
    if let value = (try? JSONSerialization.jsonObject(with: json, options: .allowFragments)) as? Int {
        print(value) // 22
    }
    

    However, JSONDecoder has no such option and does not accept top-level objects which are not arrays or dictionaries. One can see in the source code that the decode() method calls JSONSerialization.jsonObject() without any option:

    open func decode(_ type: T.Type, from data: Data) throws -> T {
        let topLevel: Any
        do {
           topLevel = try JSONSerialization.jsonObject(with: data)
        } catch {
            throw DecodingError.dataCorrupted(DecodingError.Context(codingPath: [], debugDescription: "The given data was not valid JSON.", underlyingError: error))
        }
    
        // ...
    
        return value
    }
    

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