Clean way to keep original variable and destruction at the same time

Question

Is there a cleaner way to do this (with anything that is at least an ES draft and has a babel plugin, i.e., ES6, ES7, etc.):

const { a, b } = result = doSome         


        

Answer 1

Idea 1

Create this helper function:

function use(input, callback) {
    callback(input, input);
}

and use it like:

use(doSomething(), (result, {a, b}) => {
    // Do something with result as a whole, or a and b as destructured properties.
});

For example:

use ({a: "Hello", b: "World", c: "!"}, (result, {a, b}) => {
  console.log(result);
  console.log(a);
  console.log(b);
});

// generates
// {a: "Hello", b: "World", c: "!"}
// Hello
// World

They're not const, but they're scoped, for better or worse!

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Idea 2

Combine array and object deconstruction. Create this helper function:

const dup = input => [input, input];

And then deconstruct away like so:

const [result, {a, b}] = dup(doSomething());

Now, your result, a, and b are all consts.