In Python, what determines the order while iterating through kwargs?

Question

In python, I wrote this function to teach myself how **kwargs works in Python:

def fxn(a1, **kwargs):
    print a1
    for k in kwargs:
                 


        

Answer 1

This has finally been introduced in the 3.6 release: dicts are now ordered, therefore the keyword argument order is preserved.

Python 3.6.0 (default, Jan 13 2017, 13:27:48) 
>>> def print_args(**kwargs):
...     print(kwargs.keys())
... 
>>> print_args(first=1, second=2, third=3)
dict_keys(['first', 'second', 'third'])