Access to method pointer to protected method?

Question

This code:

class B {
 protected:
  void Foo(){}
}

class D : public B {
 public:
  void Baz() {
    Foo();
  }
  void Bar() {
    printf(\"%x\\n\", &B::F         


        

Answer 1

Your post doesn't answer "Why can I call a protected method but not take its address?"

class D : public B {
 public:
  void Baz() {
    // this line
    Foo();
    // is shorthand for:
    this->Foo();
  }
  void Bar() {
    // this line isn't, it's taking the address of B::Foo
    printf("%x\n", &B::Foo);

    // not D:Foo, which would work
    printf("%x\n", &D::Foo);

  }
}