C++ virtual override functions with same name

Question

I have something like that (simplified)

class A
{
  public:
    virtual void Function () = 0;
};

class B
{
  public:
    virtual void Function () = 0;
};

c         


        

Answer 1

I can suggest another way to resolve this issue. You can add wrapper Typed which changes Function signature by adding dummy parameter. Thus you can distinguish methods in your implementation.

class A {
public:
  virtual void Function() = 0;
  virtual ~A() = default;
};

class B {
public:
  virtual void Function() = 0;
  virtual ~B() = default;
};

template
class Typed : public T {
public:
  virtual void Function(T* dummy) = 0;
  void Function() override {
    Function(nullptr);
  }
};

class Impl : public Typed, public Typed {
public:
  void Function(A* dummy) override {
    std::cerr << "implements A::Function()" << std::endl;
  }
  void Function(B* dummy) override {
    std::cerr << "implements B::Function()" << std::endl;
  }
};

The benefit of such solution is that all implementation are placed in one class.