I\'m wondering if anyone knows of a way to measure string similarity in BigQuery.
Seems like would be a neat function to have.
My case is i need to compare
While I was looking for the answer Felipe above, I worked on my own query and ended up with two versions, one which I called string approximation and another string resemblance.
The first is looking at the shortest distance between letters of source string and test string and returns a score between 0 and 1 where 1 is a complete match. It will always score based on the longest string of the two. It turns out to return similar results to the Levensthein distance.
#standardSql
CREATE OR REPLACE FUNCTION `myproject.func.stringApproximation`(sourceString STRING, testString STRING) AS (
(select avg(best_result) from (
select if(length(testString)
The second is a variation of the first, where it will look at sequences of matching distances, so that a character matching at equal distance from the character preceding or following it will count as one point. This works quite well, better than string approximation but not quite as well as I would like to (see example output below).
#standarSql
CREATE OR REPLACE FUNCTION `myproject.func.stringResemblance`(sourceString STRING, testString STRING) AS (
(
select avg(sequence)
from (
select ref,
if(array_length(array(select * from comparison.collection intersect distinct
(select * from comparison.before))) > 0
or array_length(array(select * from comparison.collection intersect distinct
(select * from comparison.after))) > 0
, 1, 0) as sequence
from (
select ref,
collection,
lag(collection) over (order by ref) as before,
lead(collection) over (order by ref) as after
from (
select if(length(testString) < length(sourceString), sourceoffset, testoffset) as ref,
array_agg(result ignore nulls) as collection
from (
select *,
if(source = test, abs(sourceoffset - (testoffset)), null) as result
from unnest(split(lower(sourceString),'')) as source with offset sourceoffset
cross join
(select *
from unnest(split(lower(testString),'')) as test with offset as testoffset)
) as results
group by ref
)
) as comparison
)
)
);
Now here is a sample of result:
#standardSQL
with test_subjects as (
select 'benji' as name union all
select 'benjamin' union all
select 'benjamin alan artis' union all
select 'ben artis' union all
select 'artis benjamin'
)
select name, quick.stringApproximation('benjamin artis', name) as approxiamtion, quick.stringResemblance('benjamin artis', name) as resemblance
from test_subjects
order by resemblance desc
This returns
+---------------------+--------------------+--------------------+
| name | approximation | resemblance |
+---------------------+--------------------+--------------------+
| artis benjamin | 0.2653061224489796 | 0.8947368421052629 |
+---------------------+--------------------+--------------------+
| benjamin alan artis | 0.6078947368421053 | 0.8947368421052629 |
+---------------------+--------------------+--------------------+
| ben artis | 0.4142857142857142 | 0.7142857142857143 |
+---------------------+--------------------+--------------------+
| benjamin | 0.6125850340136053 | 0.5714285714285714 |
+---------------------+--------------------+--------------------+
| benji | 0.36269841269841263| 0.28571428571428575|
+----------------------------------------------------------------
Edited: updated the resemblance algorithm to improve results.