iOS: How do I generate 8 unique random integers?

Question

I need to generate 8 random integers, but they need to be unique, aka not repeated.

For example, I want 8 numbers within the range 1 to 8.

I\'ve seen arc4ran

Answer 1

Try this code...this will give you all the possible unique number set in Mutable array...

-(NSInteger) randomNumber {
NSInteger newRandomNumber = (NSInteger) arc4random() % 10;
NSInteger uniqueNumber;
if ([self.arrayContainingNumbers containsObject: [NSNumber numberWithInteger:newRandomNumber]]) {
    [self randomNumber];
    } else {
    [self.arrayContainingNumbers addObject: [NSNumber numberWithInteger:newRandomNumber]];
}
uniqueNumber = [[self.mutableArrayContainingNumbers lastObject]integerValue];
     NSLog(@"new Unique Number is %ld",(long)uniqueNumber);

return uniqueNumber;  
}

Don't forget to add this method :)

    -(NSMutableArray *) arrayContainingNumbers {
if (!_mutableArrayContainingNumbers) {
    _mutableArrayContainingNumbers = [[NSMutableArray alloc] init];
}
return _mutableArrayContainingNumbers; 
}