Why doesn't this python keyboard interrupt work? (in pycharm)

Question

My python try/except loop does not seem to trigger a keyboard interrupt when Ctrl + C is pressed while debugging my code in pycharm. My code look like this:

Answer 1

You can also use PyCharm's Python console and use Ctrl + C, if you catch the exception that PyCharm raises when Ctrl + C is pressed. I wrote a short function below called is_keyboard_interrupt that tells you whether the exception is KeyboardInterrupt, including PyCharm's. If it is not, simply re-raise it. I paste a simplified version of the code below.

When it is run:

• type 'help' and press Enter to repeat the loop.
• type anything else and press Enter to check that ValueError is handled properly.
• Press Ctrl + C to check that KeyboardInterrupt is caught, including in PyCharm's python console.

Note: This doesn't work with PyCharm's debugger console (the one invoked by "Debug" rather than "Run"), but there the need for Ctrl + C is less because you can simply press the pause button.

I also put this on my Gist where I may make updates: https://gist.github.com/yulkang/14da861b271576a9eb1fa0f905351b97

def is_keyboard_interrupt(exception):
    # The second condition is necessary for it to work with the stop button
    # in PyCharm Python console.
    return (type(exception) is KeyboardInterrupt
            or type(exception).__name__ == 'KeyboardInterruptException')

try:
    def print_help():
        print("To exit type exit or Ctrl + c can be used at any time")
    print_help()

    while True:
        task = input("What do you want to do? Type \"help\" for help:- ")
        if task == 'help':
            print_help()
        else:
            print("Invalid input.")

            # to check that ValueError is handled separately
            raise ValueError()

except Exception as ex:
    try:
        # Catch all exceptions and test if it is KeyboardInterrupt, native or
        # PyCharm's.
        if not is_keyboard_interrupt(ex):
            raise ex

        print('KeyboardInterrupt caught as expected.')
        print('Exception type: %s' % type(ex).__name__)
        exit()

    except ValueError:
        print('ValueError!')