Removing syntactic sugar: List comprehension in Haskell

Question

Can I unsugar list comprehension in this expression:

[(i,j) | i <- [1..4], j <- [i+1..4]]

This is the output:

[(1,2),         


        

Answer 1

concatMap (\i -> map (\j -> (i, j)) [i+1 .. 4]) [1 .. 4]