std::make_shared with std::initializer_list

Question

#include 
#include 

class Base
{
public:
    Base() {}
};

class Derived : public Base
{
public:
    Derived() {}
    Derived(std::ini         


        

Answer 1

For this to work, you need to create a custom make_shared_from_list, as make_shared does not support non-explicit initializer lists. The reason is described well by @brian.

I would use a traits class to map a type T to the type of initializer list.

templatestruct list_init{};// sfinae support
template<> struct list_init{using type=std::pair>;};

templateusing list_init_t=typename list_init::type;

template
std::shared_ptr make_shared_from_list( std::initializer_list> list ){
  return std::make_shared( std::move(list) );
}

or something like that.

Alternatively, "cast" the {...} to the initializer_list directly (not a cast, but rather a construction) may work.

In theory, sufficient reflection metaprogramming support would allow shared_ptr to do this without the traits class, bit that is pretty far down the pipe.