var arr = [4, 5, 7, 8, 14, 45, 76]; function even(a) { var ar = []; for (var i = 0; i < a.length; i++) { ar.push(a[2 * i + 1]); } return ar; } ale
This will work on 2018 :)
take the odd indexes and apply to filter
var arr = [4, 5, 7, 8, 14, 45, 76,5]; let filtered=arr.filter((a,i)=>i%2===1); console.log(filtered);