How to properly report an exit status in batch?

Question

I\'m facing a weird situation where a batch file I wrote reports an incorrect exit status. Here is a minimal sample that reproduces the problem:

bug.cmd

Answer 1

The following is working ok invoking the bat with CALL:

bug.bat:

echo before

if "" == "" (
        echo first if
        exit /b 1

        if "" == "" (
                echo second if
        )
)

test.bat:

call bug.bat
echo Exit Code is %ERRORLEVEL%

Exit Code is 1