Sum of all digits for a given Positive Number [closed]

Answer 1

I changed your method to this, then it gives the requested result:

public int compute(int methParam) {
    int sum = 0;
    for (int i = 0; methParam > 10; i++) {
        int currentDigit = methParam % 10;
        methParam = methParam / 10;
        sum = sum + currentDigit;
    }
    if (sum + methParam > 10) {
        return compute(sum + methParam);
    } else {
        return sum + methParam;
    }
}

Please note that i moved the declaration of sum inside the method, instead of making it a field.