Sum of all digits for a given Positive Number [closed]

Answer 1

Many wrong answers here. Here's what OP wants:

Method return should be like if entered a number, suppose 345, then output should be 3+4+5=12 --> 1+2 = 3.

This will do the job:

public static int compute(int param) {
    int sum = 0;
    do {
        sum = 0;
        while (param > 0) {
            sum += param % 10;
            param /= 10;
        }
        param = sum;
    } while (sum >= 10);
    return sum;
}