std::enable_if to conditionally compile a member function

Question

I am trying to get a simple example to work to understand how to use std::enable_if. After I read this answer, I thought it shouldn\'t be too hard to come up wi

Answer 1

I made this short example which also works.

#include 
#include 

class foo;
class bar;

template
struct is_bar
{
    template
    typename std::enable_if::value, bool>::type check()
    {
        return true;
    }

    template
    typename std::enable_if::value, bool>::type check()
    {
        return false;
    }
};

int main()
{
    is_bar foo_is_bar;
    is_bar bar_is_bar;
    if (!foo_is_bar.check() && bar_is_bar.check())
        std::cout << "It works!" << std::endl;

    return 0;
}

Comment if you want me to elaborate. I think the code is more or less self-explanatory, but then again I made it so I might be wrong :)

You can see it in action here.