Checking if a double (or float) is NaN in C++

Question

Is there an isnan() function?

PS.: I\'m in MinGW (if that makes a difference).

I had this solved by using isnan() from , which doe

Answer 1

It seems to me that the best truly cross-platform approach would be to use a union and to test the bit pattern of the double to check for NaNs.

I have not thoroughly tested this solution, and there may be a more efficient way of working with the bit patterns, but I think that it should work.

#include 
#include 

union NaN
{
    uint64_t bits;
    double num;
};

int main()
{
    //Test if a double is NaN
    double d = 0.0 / 0.0;
    union NaN n;
    n.num = d;
    if((n.bits | 0x800FFFFFFFFFFFFF) == 0xFFFFFFFFFFFFFFFF)
    {
        printf("NaN: %f", d);
    }

    return 0;
}